+128475 2log ( a -2b) = log a + log b
By log properties, we can write
log (a - 2b)^2 = log (ab)
This implies that
(a -2b)^2 = ab simplify
a^2 - 4ab + 4b^2 = ab subtract ab from both sides
a^2 -5ab + 4b^2 = 0 factor as
(a - 4b) ( a - b) = 0
So...either
a - 4b = 0 or a - b = 0
a = 4b ⇒ a/b = 4 a = b
The second answer (in red) would mean that b would have to be negative in log (a - 2b)......but this isn't defined for log b
So
a/b = 4
