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A truck travels beneath an airplane that is moving 120 km/h at an angle of 46◦ to the ground. How fast must the truck travel to stay beneath the airplane?

Guest Sep 30, 2017

Best Answer 

 #1
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cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

hectictar  Sep 30, 2017
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1+0 Answers

 #1
avatar+4806 
+2
Best Answer

 

cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

hectictar  Sep 30, 2017

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