+0  
 
+1
783
1
avatar

A truck travels beneath an airplane that is moving 120 km/h at an angle of 46◦ to the ground. How fast must the truck travel to stay beneath the airplane?

 Sep 30, 2017

Best Answer 

 #1
avatar+9460 
+2

 

cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

 Sep 30, 2017
 #1
avatar+9460 
+2
Best Answer

 

cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

hectictar Sep 30, 2017

0 Online Users