+0  
 
+1
202
1
avatar

A truck travels beneath an airplane that is moving 120 km/h at an angle of 46◦ to the ground. How fast must the truck travel to stay beneath the airplane?

Guest Sep 30, 2017

Best Answer 

 #1
avatar+7153 
+2

 

cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

hectictar  Sep 30, 2017
 #1
avatar+7153 
+2
Best Answer

 

cos 46°  =  b / 120

 

120 cos 46°  =  b

 

b  ≈  83.359  km / hr

hectictar  Sep 30, 2017

9 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.