+0  
 
0
606
1
avatar
how do I solve f(x) = 3|x^2-7| + 2x / -4 for f(-6)
 Nov 20, 2013
 #1
avatar
0
First of all, just in case you don't know, f(x) means the same thing as y. When it tells you to solve for f(any number), ((f of -6 in this case)), you plug that number in for all the x's in the equation.

First you plug in your (-6) for x. So 3I(-6)^2-7I + 2(-6) / -4

Negative 6 squared=36 and 36-7=29 29*3=87 87 - 12

3 I 36 - 7 I + 2(-6) / -4

Negative 6 squared = 36, so

3 I 36-7 I + 2(-6) / -4

And 36 - 7 = 29, so

3 I 29 I + 2(-6) / -4

The "I" symbols mean absolute value, and the absolute value of 29 = 29, so

3(29) + 2(-6) / -4

Now, here's the simpler math. 3*29 = 87 and 2*(-6) = -12, and adding negative 12 is the same as subtracting 12

(87 - 12) / -4

Obviously, 87 - 12 = 75, so

75 / -4

Now divide 75 by -4

75 / -4 = -18.75 ( as a decimal) or -75/4 as a fraction. MAKE SURE TO WRITE YOUR ANSWER LIKE f(-6) = -18.75 or f(-6) = -75/4


I hope this helps!!! Good luck!!!!
 Nov 20, 2013

1 Online Users

avatar