Help please!

In standard form, determine the equation of the quadratic equation that has x-intercepts, √5 and -√5 and contains the point (3,3)?

I understand how to get (a).

3=a(3+√5)(3-√5)

3=a(9-5)

3=4a

a=3/4

then y=3/4(x+√5)(x-√5)

But I'm stuck at where you have to convert it to standard form?

I appreciate the help!