In standard form, determine the equation of the quadratic equation that has x-intercepts, √5 and -√5 and contains the point (3,3)?
I understand how to get (a).
3=a(3+√5)(3-√5)
3=a(9-5)
3=4a
a=3/4
then y=3/4(x+√5)(x-√5)
But I'm stuck at where you have to convert it to standard form?
I appreciate the help!