+0

0
68
4

Express the infinite series $$\frac{3}{206}+\frac{9}{2\cdot103^2}+\frac{27}{2\cdot103^3}+\cdots$$as a terminating decimal.



A particular geometric sequence has strictly decreasing terms. After the first term, each successive term is calculated by multiplying the previous term by $\frac{m}{7}$. If the first term of the sequence is positive, how many possible integer values are there for $m$?
Guest May 21, 2018
#1
+1

Guest May 21, 2018
#2
+92888
+1

Express the infinite series

$$\frac{3}{206}+\frac{9}{2\cdot103^2}+\frac{27}{2\cdot103^3}+\cdots$$

as a terminating decimal.

This is a ordinary GP

$$S_\infty=\frac{a}{1-r}$$

If you have done GPs this will be easy. If not then you better say so.

Melody  May 21, 2018
#3
0

I did not

Guest May 22, 2018
#4
0

S =[3/206] / [1 - 3/103]

S =[3/206] x [103/100]

S = 309 /20,600

S = 3 / 200

S = 0.015

Guest May 22, 2018