Help Please!!

https://web2.0calc.com/questions/please-help_29935#r1

1.  We have something like this

       D

    1200

       B  ___________ C

                              53°      

     400           -

                 -        

        A  

A  = point where he stands

B =  point on opposite shore directly across  from Daniel

C =  boat ramp

D =  his campsite

2.  We  can find the distance he swims  (A to C)  as follows

Triangle  ABC  is a right triangle  with angle  ABC  = 90°

And AC  is the hypotenuse

And  AB  is the opposite side to the 53° angle

So

sin 53°  =   400 / AC         rearrange as

AC  =  400 / sin 53  ≈   500.85 ft

So....the time it takes to swim this distance  is

500.85   / 150   ≈    3.34  min

3.  To answer this....we need to  first know the distance BC.....this is given by

tan 53°  =  400 / BC      rearrange as

BC  =  400 / tan 53°  ≈    301.42 ft

And  DBC  is a right triangle with  hypotenuse  DC.....this is the distance from the boat ramp to the campsite

So

DC  = sqrt (DB^2 + BC^2)

DC =  sqrt ( 1200^2 + 301.42^2 )  ≈  1237.28  ft

4.  Time it takes to jog to the campsite from the boat ramp  =

Note :  4mph   =  4 * 5280  / 3600  =   88/15  ft / sec

So     distance / rate  = time   ....so....

1237.28  /  (88/15)   =

1237.28 * 15  /  88  =  210.9  sec  ≈    210.9/60  ≈  3.52  min

I already answered this a couple of days ago.

And I see EP found an even earlier answer of mine.

Half the infor was missing then.  On scanning this new question, some of the required info is still missing.

You did not even bother to comment on my comprehensive answer!

I guess you are just another brat here who reposts without comment when they do not get the answer that they want.

Here was my second answer

https://web2.0calc.com/questions/help_76453