The graph of the equation \(y=ax^2+bx+c\) has the line \(x=4\) as an axis of symmetry. Find \(\frac{b}{a}\)
y = ax^2 + bx + c
This is a parabola that turns upward.....the x coordinate of the vertex = 4
And the x coordinate of the vertex = -b / [ 2a] = 4
-b/a = 8
So b / a = -8
Aw man! I was so close! I got 8. But thanks for the help CPhill!
-OP
Maybe just a sign error ......
