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The graph of the equation \(y=ax^2+bx+c\) has the line \(x=4\) as an axis of symmetry. Find \(\frac{b}{a}\)

 Apr 10, 2020
 #1
avatar+111329 
+2

y = ax^2  + bx  +  c

 

This  is  a parabola  that turns upward.....the x coordinate  of the  vertex = 4

 

And  the x coordinate of the  vertex  =  -b / [ 2a]  =  4

 

-b/a  =  8

 

So       b / a   =  -8

 

 

cool cool cool

 Apr 10, 2020
 #2
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+1

Aw man! I was so close! I got 8. But thanks for the help CPhill!

 

-OP

Guest Apr 10, 2020
 #3
avatar+111329 
+2

Maybe just a sign error  ......

 

 

cool cool cool

CPhill  Apr 10, 2020

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