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Prove that  sinθ=eiθeiθ2i

 Jul 16, 2021
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sinθ=eiθeiθ2i RHS=[cosθ+isinθ][cos(θ)+isin(θ)]2iRHS=[cosθ+isinθ][cos(θ)isin(θ)]2iRHS=2isinθ2iRHS=sinθ RHS=LHSQ.E.D.

 Jul 17, 2021

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