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$ABCD$ is a parallelogram such that $AB=\sqrt{3}\cdot BC.$ Diagonals $\overline{AC}$ and $\overline{BD}$ intersect at $X$ and $\angle ABC=\angle BXC.$ Find the measure of $\angle ACB$ in degrees.

Dec 21, 2019

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Answered here    :  https://web2.0calc.com/questions/geometry-math-question-help

Dec 21, 2019