By what integer factor must 9! be multiplied to equal 11!?
\(\begin{array}{|rcll|} \hline 9!\times 10 \times 11 &=& 11! \\ 9! \times 110 &=& 11! \\ \hline \end{array}\)
The integer factor is 110.
Yes, 9!=9*8*7*6*5*4*3*2*1
11!=11*10*9*8*7*6*5*4*3*2*1.
We see that 11*10 is extra, or \(\boxed{110}\)
