Help please

By what integer factor must 9! be multiplied to equal 11!?

$\begin{array}{|rcll|} \hline 9!\times 10 \times 11 &=& 11! \\ 9! \times 110 &=& 11! \\ \hline \end{array}$

The integer factor is 110.

Yes, 9!=9*8*7*6*5*4*3*2*1

11!=11*10*9*8*7*6*5*4*3*2*1.

We see that 11*10 is extra, or $\boxed{110}$