The height h in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t^2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?

Guest Sep 14, 2020

#1**0 **

It would be **4 seconds. **We want to find out how many seconds it will take until the ball hits the ground, making our h = 0. Adding \(-16t^2\)to both sides, we get \(16t^2 = 64t\). Dividing both sides by \(16t\) we get, \(t = 4\).

Awesomeguy Sep 15, 2020