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How many ways are there to put 4 indistinguishable balls in 3 distinsuishable boxes?

 Sep 29, 2020
 #1
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Looks like three ways to me. 

 

              1     1     2    

              1     2     1    

              2     1     1    

 Sep 29, 2020
 #2
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I do not know the answer but I think there are other ways like

4 0 0

0 4 0 

 

3 0 1

1 0 3

2 2 0

0 2 2      etc

ElectricPavlov  Sep 29, 2020
 #3
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With no restrictions and empty boxes allowed, we have:

 

[4 + 3 - 1] nCr [3 - 1] = 6 C 2 = 15 ways

 Sep 29, 2020

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