If a chemist needs to make 60 ml of a solution using 5% solution of acid and has 3% and 8% acid how much would she need of each to make 5% solution of acid
+36916 Total soln = 60ml 0f 5 %
Volume of 3% = x then the remainder, 60-x is the 8% solution
total of constituents = total of final solution
.03 x + .08 (60-x) = .05 (60) solve for x the amount of 3% needed.....then the amount of 5% needed is 60 - x 
+36916 Total soln = 60ml 0f 5 %
Volume of 3% = x then the remainder, 60-x is the 8% solution
total of constituents = total of final solution
.03 x + .08 (60-x) = .05 (60) solve for x the amount of 3% needed.....then the amount of 5% needed is 60 - x
