If a chemist needs to make 60 ml of a solution using 5% solution of acid and has 3% and 8% acid how much would she need of each to make 5% solution of acid

Guest Feb 5, 2020

#1**+2 **

Total soln = 60ml 0f 5 %

Volume of 3% = x then the remainder, 60-x is the 8% solution

total of constituents = total of final solution

.03 x + .08 (60-x) = .05 (60) solve for x the amount of 3% needed.....then the amount of 5% needed is 60 - x

ElectricPavlov Feb 5, 2020

#1**+2 **

Best Answer

Total soln = 60ml 0f 5 %

Volume of 3% = x then the remainder, 60-x is the 8% solution

total of constituents = total of final solution

.03 x + .08 (60-x) = .05 (60) solve for x the amount of 3% needed.....then the amount of 5% needed is 60 - x

ElectricPavlov Feb 5, 2020