For the graph of a certain quadratic y=ax^2+bx+c , the vertex of the parabola is (3,7)and one of the x-intercepts is (-2,0) . What is thex -coordinate of the other x -intercept?
Please give me the direct answer.
Thanks In Advance!
Because of symmetry of the roots around the vertex, we can solve for the other x intercept thusly :
( 3 + [ 3 - - 2] , 0 ) = ( 3 + 5 , 0 ) = (8, 0)
So....the other x intercept is ( 8, 0)