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How many L of a 40% alcohol solution must be mixed with 6 L of a 50% alcohol solution to make a 46% solution

 Feb 21, 2020
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(percent x amount) + (percent x amount)  =  final percent x final amount

                                  0.40 · x  +  0.50 · 6  =  0.46 · (x + 6)      [x is the unknown number of liters of the 40% solution]

                                             0.40x + 3.00  =  0.46x + 2.76

subtract 0.40x from both sides:         3.00  =  0.06x + 2.76

subtract 2.76 from both sides:           0.24  =  0.06x

divide both sides by 0.06:                       4  =  x

 Feb 21, 2020

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