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Find the vertex of the graph of the equation $x -y^2 + 6y =8$.

Guest Feb 16, 2018
 #1
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(-1,3)

Guest Feb 16, 2018
 #2
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+1

x - y^2 + 6y  = 8      rewrite as

 

x  =  y^2 - 6y  + 8     

 

This one  is a little different  from the "normal" vertical parabola

It turns sideways and opens to the right

 

The y coordinate of the vertex is given by 

 

- (-6) /2(1)  =  3

 

So  the x coordinate of the vertex  is

 

x  =  (3)^2 - 6(3) + 8

 

x  = 9 - 18 + 8

 

x  = -1

 

So......the vertex  is    (-1, 3)

 

 

Here's a graph  ; https://www.desmos.com/calculator/wicxhszt9d

 

 

cool cool cool

CPhill  Feb 17, 2018

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