Find the largest value of c such that \(\frac{c^2 + 6c -27}{c-3} +2c = 23\)
Factor the polynomial in the numerator as (c - 3) ( c + 9)
This gives us
(c+ 9) + 2c = 23
3c + 9 = 23
3c = 14
c = 14 / 3
+82 
