Find x such that \($\lfloor x \rfloor + x = \dfrac{13}{3}$\). Express x as a common fraction.

Thanks in advance!!!

HelpBot Jul 17, 2020

#1**+1 **

Next time please present your question properly by deleting the dollar signs

\(\lfloor x \rfloor + x = \dfrac{13}{3}\\ \lfloor x \rfloor + x =4 \dfrac{1}{3}\\ \text{obviously}\;\;\lfloor x \rfloor\;\;\text{is a whole number }\\ so\\ \lfloor x \rfloor + \lfloor x \rfloor + \dfrac{1}{3} = 4 \dfrac{1}{3}\\ so\;\;\;\lfloor x\rfloor=2\\ x=2\frac{1}{3} \)

Melody Jul 17, 2020