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Find x such that $$\lfloor x \rfloor + x = \dfrac{13}{3}$$. Express x as a common fraction.

Jul 17, 2020

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Next time please present your question properly by deleting the dollar signs

$$\lfloor x \rfloor + x = \dfrac{13}{3}\\ \lfloor x \rfloor + x =4 \dfrac{1}{3}\\ \text{obviously}\;\;\lfloor x \rfloor\;\;\text{is a whole number }\\ so\\ \lfloor x \rfloor + \lfloor x \rfloor + \dfrac{1}{3} = 4 \dfrac{1}{3}\\ so\;\;\;\lfloor x\rfloor=2\\ x=2\frac{1}{3}$$

Jul 17, 2020
edited by Melody  Jul 17, 2020
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Oopsy. I think that was a typo. Thanks Melody :)

Jul 17, 2020