A baseball player makes 153 hits in 572 times at bat in one season
and 172 hits in 576 times at bat in the next season. For both seasons
combined, what percent of the times at bat were hits? Round your
answer to one decimal place.
+354 The percent the player hits in the first season is $${\frac{{\mathtt{153}}}{{\mathtt{572}}}} = {\mathtt{0.267\: \!482\: \!517\: \!482\: \!517\: \!5}}$$
The second season is $${\frac{{\mathtt{172}}}{{\mathtt{576}}}} = {\frac{{\mathtt{43}}}{{\mathtt{144}}}} = {\mathtt{0.298\: \!611\: \!111\: \!111\: \!111\: \!1}}$$
Combined, the percentage hit would be $${\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{153}}}{{\mathtt{572}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{172}}}{{\mathtt{576}}}}\right) = {\mathtt{0.283\: \!046\: \!814\: \!296\: \!814\: \!3}}$$ or 28.3%
