Tommy had some pencils in Box A and 480 pencils in Box B. When he moved 10% of the pencils from Box B to Box A, the number of pencils in Box A increased by 30%. He then sold 75% of the pencils in Box A and gave away 75% of the remaining pencils in Box A. How many pencils were left in Box A in the end?

tacoBRO1023 Jun 15, 2022

#1**+1 **

Let A be the number originally in Box A

After he moved 10% of the pencils in B to A it contained

A + .10 (480) = 1.30 A

A + 48 = 1.30 A

48 = 1.30 A - A

48 = .30A

A = 48/.30 = 160

So......there were 160 + 48 = 208 pencils in the box after this

He sol 75% of these...so

208 (.25) = 52 remained after this

And he gave 75% of these away....so

52 (.25) = 13 remained at the end

CORRECTED ANSWER

CPhill Jun 15, 2022

#2**+2 **

Let x = # of pencils in Box A originally

x + 480 (80%) = x + 30% x

48/0.3 = 0.3x/0.3

x = 160

* 160 + 48 = 208

* 208 (1 - 0.75) = 208 (0.25) = 52

* 52 (1 - 0.75) = 52 (0.25) = 13 pencils left

Slimesewer Jun 15, 2022