+113 Tommy had some pencils in Box A and 480 pencils in Box B. When he moved 10% of the pencils from Box B to Box A, the number of pencils in Box A increased by 30%. He then sold 75% of the pencils in Box A and gave away 75% of the remaining pencils in Box A. How many pencils were left in Box A in the end?
+129905 Let A be the number originally in Box A
After he moved 10% of the pencils in B to A it contained
A + .10 (480) = 1.30 A
A + 48 = 1.30 A
48 = 1.30 A - A
48 = .30A
A = 48/.30 = 160
So......there were 160 + 48 = 208 pencils in the box after this
He sol 75% of these...so
208 (.25) = 52 remained after this
And he gave 75% of these away....so
52 (.25) = 13 remained at the end
CORRECTED ANSWER
+237 Let x = # of pencils in Box A originally
x + 480 (80%) = x + 30% x
48/0.3 = 0.3x/0.3
x = 160
* 160 + 48 = 208
* 208 (1 - 0.75) = 208 (0.25) = 52
* 52 (1 - 0.75) = 52 (0.25) = 13 pencils left
