Suppose K is a constant, such that no pair of real numbers (x, y) satisfies this system of equations:
6x + 4y = 7
Kx + 8y = 7
What is the value of K?
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Let's saolve the system of equations
Multiply first equation by -2
-12x-8y=-14 and add to second equation
kx+8y =7
(-12+k)x = -7
x = -7 / (-12+k) Thus when k = 12 this would not be a real number (denominator would be ' 0 ' )