+0  
 
0
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2
avatar+111 

Suppose K is a constant, such that no pair of real numbers (x, y) satisfies this system of equations:

 

6x + 4y = 7

 

Kx + 8y = 7

 

What is the value of K?

 

thank you ! :)

 May 26, 2020
 #1
avatar+28025 
+2

Let's saolve the system of equations

Multiply first equation by -2

-12x-8y=-14    and add to second equation

kx+8y =7

(-12+k)x = -7

x = -7 / (-12+k)          Thus when k = 12  this would not be a real number     (denominator would be ' 0 ' ) 

 May 26, 2020
 #2
avatar+111 
0

i get it now, thank you so much electricpavlov!! :D

andrewstanells  May 26, 2020

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