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1.The expression 6y^2-y-51 can be rewritten as (3Ay+B)(y-C), where A, B, and C are positive integers. Find (AC)^2 - B.
2.The points (1,-2) and (-4,10) are adjacent vertices of a square. What is the perimeter of the square?
3.Harry and Sandy wish to meet at a point in Hogwarts that is at the midpoint of their coordinates. Harry is standing at (9,-2), and Sandy is standing at (1,6). At what coordinate will they meet?

Thanks!

 Jun 11, 2019
 #1
avatar+102937 
+2

1. 6y^2 - y - 51     =   (6y +17) (y  -  3)  =  (3*2y + 17) ( y - 3)  

 

A = 2  B = 17  C  = 3

 

So

 

(AC)^2 - B   =   (2*3)^2 - 17  =  6^2 - 17  =  36 - 17  =  19

 

 

2. We need the distance formula * 4 =  √ [( -4 - 1)^2 + (-2 - 10)^2 ]  * 4   =

 

√ [  (-5)^2 + (-12)^2 ]  * 4  =

 

√ [25 + 144 ] * 4  =

 

√169 * 4

 

13 * 4  =   

 

52 = the perimeter

 

 

3. Midpoint formula  [  (9+ 1)/2 , (6 - 2) /2 ]

I'll let you compute that one

 

 

 

cool cool cool

 Jun 11, 2019
 #2
avatar+253 
+1

Is the answer (5,2)?

sinclairdragon428  Jun 11, 2019
 #3
avatar+253 
0

Thanks!

sinclairdragon428  Jun 11, 2019
 #4
avatar+102937 
0

Yep....!!!

 

cool cool cool

CPhill  Jun 11, 2019

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