1.The expression 6y^2-y-51 can be rewritten as (3Ay+B)(y-C), where A, B, and C are positive integers. Find (AC)^2 - B.

2.The points (1,-2) and (-4,10) are adjacent vertices of a square. What is the perimeter of the square?

3.Harry and Sandy wish to meet at a point in Hogwarts that is at the midpoint of their coordinates. Harry is standing at (9,-2), and Sandy is standing at (1,6). At what coordinate will they meet?

Thanks!

sinclairdragon428 Jun 11, 2019

#1**+2 **

1. 6y^2 - y - 51 = (6y +17) (y - 3) = (3*2y + 17) ( y - 3)

A = 2 B = 17 C = 3

So

(AC)^2 - B = (2*3)^2 - 17 = 6^2 - 17 = 36 - 17 = 19

2. We need the distance formula * 4 = √ [( -4 - 1)^2 + (-2 - 10)^2 ] * 4 =

√ [ (-5)^2 + (-12)^2 ] * 4 =

√ [25 + 144 ] * 4 =

√169 * 4

13 * 4 =

52 = the perimeter

3. Midpoint formula [ (9+ 1)/2 , (6 - 2) /2 ]

I'll let you compute that one

CPhill Jun 11, 2019