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deleted.

 Jun 11, 2019
edited by sinclairdragon428  Nov 20, 2019
 #1
avatar+104963 
+2

1. 6y^2 - y - 51     =   (6y +17) (y  -  3)  =  (3*2y + 17) ( y - 3)  

 

A = 2  B = 17  C  = 3

 

So

 

(AC)^2 - B   =   (2*3)^2 - 17  =  6^2 - 17  =  36 - 17  =  19

 

 

2. We need the distance formula * 4 =  √ [( -4 - 1)^2 + (-2 - 10)^2 ]  * 4   =

 

√ [  (-5)^2 + (-12)^2 ]  * 4  =

 

√ [25 + 144 ] * 4  =

 

√169 * 4

 

13 * 4  =   

 

52 = the perimeter

 

 

3. Midpoint formula  [  (9+ 1)/2 , (6 - 2) /2 ]

I'll let you compute that one

 

 

 

cool cool cool

 Jun 11, 2019
 #2
avatar+397 
0

Is the answer (5,2)?

sinclairdragon428  Jun 11, 2019
 #3
avatar+397 
-1

Thanks!

sinclairdragon428  Jun 11, 2019
 #4
avatar+104963 
0

Yep....!!!

 

cool cool cool

CPhill  Jun 11, 2019

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