The quadratic $x^2-4x-14=3x+16$ has two solutions. What is the positive difference between these solutions?
Thanks!
x^2 - 4x - 14 = 3x + 16 rearrange as
x^2 -7x -30 = 0 factor
(x -10) ( x + 3) = 0
Set each factor to 0 and solve for x
x - 10 = 0 x + 3 = 0
x =10 x = -3
The positive difference is 10 - (-3) = 13
+379 
