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Let \(f(x) = \begin{cases} k(x) &\text{if }x>3, \\ x^2-6x+12&\text{if }x\leq3. \end{cases} \) Find the function k(x) such that f is its own inverse.

 Jul 10, 2022
 #1
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Find the function k(x) such that f is its own inverse.

 

Hello Guest!

 

\(\begin{cases} {\color{blue}k(x)=\pm \sqrt{(x-3)}+3} &\text{if }\color{blue}x>3, \\ f(x)=x^2-6x+12&\text{if }x\leq3. \end{cases}\)

laugh  !

 Jul 10, 2022
 #2
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This answer is useless.

Guest Jul 10, 2022

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