Square root of h3
----------------------(over)
square root of 8
simplify plz
I dnot un,dderstand...
√h3 = √h•h•h = (√h•h)(√h) = h√h
√8 = √4•2 = (√4)(√2) = 2√2
final result is h√h over 2√2
\(\dfrac{\sqrt{h^3}}{\sqrt{8}}\\ =\dfrac{h\sqrt{h}}{2\sqrt 2}\\ =\dfrac{h\sqrt{2h}}{4}\)
