+0  
 
0
138
1
avatar

Ten people are sitting around a round table. Three of them are chosen at random to give a presentation. What is the probability that the three chosen people were sitting in consecutive seats?

Guest Jun 27, 2018
 #1
avatar+91297 
+2

We  have  C (10,3)  =  120  possible total selections of any three people

 

And  there  10  possibilities of selecting  3 people who sit together

( The first group occupies  seats 1, 2 and 3  and the last group occupies seats 10, 1 and 2)

So

1 2 3

2 3 4

3 4 5

.

.

.

10 1 2

 

So....the probability is just    10 / 120    =  1 /12

 

 

cool cool cool

CPhill  Jun 27, 2018

4 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.