+0

0
55
4

For how many integer values of 'a' does the equation

x^2 + ax + 8 = 0

have integer solutions for x?

It isn't 4.

Dec 17, 2020

#1
0

Sorry, I meant x^2 + ax + 8a = 0.

Dec 17, 2020
#2
0

Hint: use the quadratic formula as $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$and $a=1$, $b=a$ and $c=8$

Dec 17, 2020
#3
+114320
+1

x^2  + ax  + 8a   =  0

The discriminant either needs to be a perfect square  or  = 0

a^2  - 4(8a)  =  0

a^2 - 32a  =  0

a( a - 32)  =  0

If a  = 0 or 32  we will have  integer solutions  ( a double root)

So.....two  values of a  will produce integer solutions

Dec 17, 2020
#4
0

Sorry, that's incorrect. The correct answer was 8.

Dec 18, 2020