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How many ways are there to put 6 balls in 3 boxes if the balls are not distinguishable but the boxes are?

 Feb 28, 2020
 #1
avatar+111433 
+1

Assuming that we can have  empty  boxes....let  k  be the  number of balls  and  n be  the  number of boxes

 

The  number  of ways  =

 

C ( k + n - 1 , n - 1 )   =

 

C ( 6 + 3 - 1 , 3 - 1)  =

 

C ( 8, 2)  =

 

28 ways

 

 

cool cool cool

 Feb 28, 2020
 #2
avatar+108 
+3

Just use stars and bars 8C2 is 8!/6! * 2 which is equal to 28

 Feb 28, 2020
 #3
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0

Ok, Brainless, the last time I checked 8!/6! * 2 is not equal to 28 nor 8C2

Guest Feb 28, 2020
 #4
avatar+111433 
0

I think  brian  meant         

 

  8!

____ =    28

6! 2!

 

 

cool cool cool

CPhill  Feb 28, 2020

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