The function
f(z)=(−1+i3–√)z+(−23–√−18i)2f(z)=(−1+i3)z+(−23−18i)2
represents a rotation around some complex number c. Find c.
I don't know how to proceed, help would be appreciated.
Thank you :)
Could you clarify please, re the square root signs and the missing f(z) at the end.
A rotation is of the form y - c = e^(i*theta)*(z - c). Solving for c, we get c = 5 - 2i.
+12 
