What is the least positive integer value of x such that $(2x)^2 + 2 * 37 * 2x + 37^2$ is a multiple of 47?
By trial and error....I get that x = 5
(2 * 5)^2 + 2*37*2(5) + 37^2 = 2209
2209 / 47 = 47
+379 
