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What is the least positive integer value of x such that $(2x)^2 + 2 * 37 * 2x + 37^2$ is a multiple of 47?

 Jun 9, 2019
 #1
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By trial and error....I get that x  = 5

 

(2 * 5)^2 + 2*37*2(5) + 37^2  = 2209

 

2209 / 47   = 47

 

 

cool cool cool

 Jun 9, 2019

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