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The vertices of a convex pentagon are (-1, -1), (-3, 4), (1, 7), (6, 5) and (3, -1). What is the area of the pentagon?

 Apr 3, 2020

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Draw a rectangle around the pentagon and you should get \(8 \cdot 9=72\) \(units^2\)for the rectangle. After that, you subtract the triangles on the sides of the pentagon and the answer should be \(72-9-5-6-5=47\)\(units^2\).

 Apr 3, 2020
 #1
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+1
Best Answer

Draw a rectangle around the pentagon and you should get \(8 \cdot 9=72\) \(units^2\)for the rectangle. After that, you subtract the triangles on the sides of the pentagon and the answer should be \(72-9-5-6-5=47\)\(units^2\).

Guest Apr 3, 2020

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