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If I have a right triangle with the opposite side of 132ft., the adjacent side of 190ft., and the hypotonuse side of 240ft. what are the angles of the triangle?
 Jul 24, 2013

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cos(a) = 190/240 => a = [input]arccos(190/240)[/input]
b = 90°
sin(c) = 190/240 => c = [input]arcsin(190/240)[/input]

a + b + c = [input]arccos(190/240)+90+arcsin(190/240)[/input] has to be 180 °
 Jul 25, 2013

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