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$What is the domain of the function $$j(x) = \frac{1}{x+8} + \frac{1}{x^2+8} + \frac{1}{x^3+8}~?$$ Express your answer as a union of intervals.$

Guest Nov 8, 2014

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Best Answer

We can't have a denominator with equalling 0.

Notice in the first fraction that -8 makes the denominator 0

Nothing makes the second denominator 0.

In the third fraction, -2 makes the denominator 0.

So, in terms of real numbers, the domain is (-∞, -8) U (-8, -2) U (-2, ∞)

CPhill Nov 8, 2014

CPhill · Answer 1 · 2014-11-08T08:55:16

We can't have a denominator with equalling 0.

Notice in the first fraction that -8 makes the denominator 0

Nothing makes the second denominator 0.

In the third fraction, -2 makes the denominator 0.

So, in terms of real numbers, the domain is (-∞, -8) U (-8, -2) U (-2, ∞)

Guest · Answer 2 · 2014-11-08T08:40:14

i dont know but i think its something