Dennis and James had some savings. 25% of Dennis' savings was $120 more than 1/10 of James's savings. After Dennis had spent 5/6 of his savings and James had spent 1/3 of his savings, James' savings was $70 more than Dennis' savings. how much was Dennis' savings at first?

Guest May 2, 2022

#1**0 **

D==Dennis, J==James

5/6[0.25D) =what Dennis spent

1 /6[0.25D] - what Dennis has left.

1/3[120 + 0.10J] ==2/3[120 + 0.10J] - what James has left.

0.25D ==120 + 0.10J..................................(1)

2/3[120 + 0.10J]== 1 /6[0.25D] + 70........(2), solve for D, J

**D==$560 - what Dennis had at the start**

**J ==$200 - what James had at the start.**

Guest May 2, 2022