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Dennis and James had some savings. 25% of Dennis' savings was $120 more than 1/10 of James's savings. After Dennis had spent 5/6 of his savings and James had spent 1/3 of his savings, James' savings was $70 more than Dennis' savings. how much was Dennis' savings at first?
 

 May 2, 2022
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D==Dennis,  J==James

 

 

5/6[0.25D) =what Dennis spent

1 /6[0.25D] - what Dennis has left.

 

1/3[120  +  0.10J] ==2/3[120  +  0.10J] - what James has left.

 

0.25D ==120  +  0.10J..................................(1)

2/3[120  +  0.10J]== 1 /6[0.25D] + 70........(2), solve for D, J

 

D==$560 - what Dennis had at the start

J ==$200 - what James had at the start.

 May 2, 2022

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