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Suppose
where A, B, and C are real constants. What is \[\frac{1}{x^3-x^2-21x+45}=\frac{A}{x+5}+\frac{B}{x-3} + \frac{C}{(x - 3)^2}\]?

 Jun 30, 2023
 #1
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By partial fractions, (A,B,C) = (1/8, 7/32, -1/80).

 Jun 30, 2023

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