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https://free-picload.com/image/qqGW3B

 Mar 20, 2020
 #1
avatar+111360 
+2

I think we can use  similar triangles to solve this

 

Area of smaller circle  =  pi * radius^2

 

1 = pi * radius^2

 

1 / pi  = radius^2

 

√[1/pi]  = radius  of smaller circle

 

Call the radius of the larger circle, R

 

And  we have this

 

      3√(1/pi)              3√(1/pi) + R

      _____  =       _____________   simplify    

        √(1/pi)                R

 

 

3R   =   3√(1/pi)  + R

 

2R =  3√(1/pi)

 

R  = (3/2)√(1/pi)

 

So  the area of the larger circle  =

 

pi [( 3/2) √(1/pi) ] ^2  =     

 

9/4  units^2 = 

 

 2.25 units^2

 

 

cool cool cool       

 Mar 20, 2020

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