How many 5-digit numbers have at least one 2 or one 3 among their digits?
How many 5 digit numbers are there
99999-10000+1= 90000 or
9*10*10*10*10=90000
How many are there that do not have a 2 or a 3 as any digit.
7*8^4 = 28672
So how many of them DO have at least one 2 or one 3
90000-28672 = 61328
Edited after my answer was questioned. We agree now.