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The values of a function $f(x)$ are given below: \begin{tabular}{|c||c|c|c|c|c|} \hline $x$ & 3 & 4 & 5 & 6 & 7 \\ \hline $f(x)$ & 10 & 17 & 26 & 37 & 50 \\ \hline \end{tabular} Evaluate $f^{-1}\left(f^{-1}(50)\times f^{-1}(10)+f^{-1}(26)\right)$.    thanks 

 Nov 15, 2014

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 #1
avatar+130511 
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f-1 (50) = 7

f-1 (10) = 3

f-1 (26) = 5

So ......

f-1 (7 x 3 + 5) = f-1 (21 + 5) = f-1 (26) = 5

 

 Nov 15, 2014

1+0 Answers

 #1
avatar+130511 
+8
Best Answer

f-1 (50) = 7

f-1 (10) = 3

f-1 (26) = 5

So ......

f-1 (7 x 3 + 5) = f-1 (21 + 5) = f-1 (26) = 5

 

CPhill Nov 15, 2014

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