+980 A triangle has side lengths of 10, 24, and 26. Let a be the area of the circumcircle. Let b be the area of the incircle. Compute a - b.
This is very easy!
Hints:
1/ This is the right triangle.
2/ Find the area of a triangle using Heron's formula.
3/ r = A/s
4/ R = abc/4rs
Enough from me
Right scalene triangle.
Sides: a = 10 b = 24 c = 26
Area: T = 120
Perimeter: p = 60
Semiperimeter: s = 30
Angle ∠ A = α = 22.62° = 22°37'11″ = 0.395 rad
Angle ∠ B = β = 67.38° = 67°22'49″ = 1.176 rad
Angle ∠ C = γ = 90° = 1.571 rad
Inradius: r = 4
Circumradius: R = 13
Area =Pi x r^2
Area of the Circumcircle =Pi x 13^2
Area of the Incircle =Pi x 4^2
[a - b] =13^2Pi - 4^2Pi
[a - b] = 153Pi
