A triangle has side lengths of 10, 24, and 26. Let a be the area of the circumcircle. Let b be the area of the incircle. Compute a - b.

qwertyzz Jul 18, 2020

#3**0 **

This is very easy!

Hints:

1/ This is the right triangle.

2/ Find the area of a triangle using Heron's formula.

3/ r = A/s

4/ R = abc/4rs

Enough from me

Guest Jul 18, 2020

#4**0 **

Right scalene triangle.

Sides: a = 10 b = 24 c = 26

Area: T = 120

Perimeter: p = 60

Semiperimeter: s = 30

Angle ∠ A = α = 22.62° = 22°37'11″ = 0.395 rad

Angle ∠ B = β = 67.38° = 67°22'49″ = 1.176 rad

Angle ∠ C = γ = 90° = 1.571 rad

Inradius: r = 4

Circumradius: R = 13

Area =Pi x r^2

Area of the Circumcircle =Pi x 13^2

Area of the Incircle =Pi x 4^2

[a - b] =13^2Pi - 4^2Pi

**[a - b] = 153Pi**

Guest Jul 18, 2020