Let C be a point not on line AE and D a point on line AE such that CD ⊥ AE. Meanwhile, B is a point on line CE such that AB ⊥ CE. If AB = 4, CD = 8, and AE = 5, then what is the length of CE?
- Daisy
∵∠E=∠E,∠ABE=∠CDE=90º∴By AA Similarity,△EBA∼△EDC.∵△EBA∼△EDC∴ABDC=AECE.Filling in the numbers, we get:48=5CE.Solving for CE:4CE=5⋅8⇒CE=10
The length of CE is 10.
I hope this helped,
Gavin.
