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Find the largest n so that 2^n divides 72!.

 May 31, 2020
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a=1;c=if(72! % (2^a)==0, goto2, goto3);printc, a; a++;if(a<1000, goto1, 0)

 

The largest n = 70, so that 72! mod 2^70 =0

 May 31, 2020

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