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r and s are the roots of 3x^2 + 4x + 12 = 0. Find r^2+s^2 Please help me!!!

 Jan 22, 2021
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Vieta's formulas:

r + s = 4

rs = 12

(r + s)^2 = 16

r^2 + 2rs + s^2 = 16

r^2 + 24 + s^2 = 16

r^2 + s^2 = -8

 Jan 22, 2021

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