r and s are the roots of 3x^2 + 4x + 12 = 0. Find r^2+s^2 Please help me!!!
Vieta's formulas:
r + s = 4
rs = 12
(r + s)^2 = 16
r^2 + 2rs + s^2 = 16
r^2 + 24 + s^2 = 16
r^2 + s^2 = -8
