Help on precalculus!
Usually tan has asymtope at pi/2 ( where cos = 0 )
this is changes to 1/2 of that so 2 x
tan ( 2x ) then it is shifted DOWN 5 units
tan ( 2x) - 5 now at - pi/8 y = -7
? tan (2 * - pi/8) -5 = -7
? = 2
2 tan (2x) - 5 = y