The prime factorization of 2007 is 3^2*223. How many ordered pairs of positive integers (x,y) satisfy the equation xy=2007?
5
espero que te ayude(*/ω\*)
Creo que la respuesta es 6
(1, 2007), (2007, 1), (3, 669), (669, 3), (9, 223), (223, 9)