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Let \(a_n = 4n^3 + 6n^2 + 4n + 1.\)  Find \(a_8 + a_9 + a_{10} + \dots + a_{23}.\)
 

Please help me!

 Mar 2, 2020
 #1
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Look at each of the separate terms as follows:

 

 Mar 2, 2020
 #2
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wait, so simply plug in v=8 and w=23 into each of the equations and add the results up? 

 Mar 2, 2020
 #3
avatar+30637 
+3

That's right!

Alan  Mar 2, 2020
 #4
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listfor(n,8,23,(4*n^3+6*n^2+4*n+1))

 

(2465, 3439, 4641, 6095, 7825, 9855, 12209, 14911, 17985, 21455, 25345, 29679, 34481, 39775, 45585, 51935)=327,680

 Mar 2, 2020

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