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The number of miles driven by a truck driver falls between 300 and 700, and follows a uniform distribution. What is the probability that the truck driver goes more than 650 miles in a day?

 Mar 9, 2020
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The  mean is  [  300 + 700]   /  2 =  [1000 ]  / 2  =   500 miles

 

One standard  deviation   is  34.13%  above  the  mean =  ( 1 + .3413) (500) - 500  = 170.65

 

So....the z score we need  can be  computed as

 

[  650 - 500 ]

___________   = .2236

    670.65

 

The z score table associated with this  value  is   .58706

 

So....the probability  that he drives  more  than  650  miles  per day =  1 - .58706  ≈  41.3%

 

 

 

cool cool cool

 Mar 10, 2020

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