+0  
 
0
140
1
avatar

1) Express \(\frac{2+i}{4+i}\) in the form a+bi, where a and b are real numbers.

 

2) Express \(\frac 1{1+\frac 1{1-\frac 1{1+i}}}\) in the form a+bi, where a and b are real numbers.

 

3) The complex numbers z and w satisfy |z| = |w| = 1 and zw is not equal to -1.

(a) Prove that \(\overline{z} = \frac{1}{z}\) and \(\overline{w} = \frac{1}{w}.\)

(b) Prove that \(\frac{z + w}{zw + 1}\) is a real number.

 

thank you

 Jan 7, 2022
 #1
avatar
0

3 (a) Let w = a + bi and z = c + di.  The rest is expanding.

 

(b) Let w = a + bi and z = c + di.  Then

\(\dfrac{w + z}{1 + wz} = \dfrac{a + c + bi + di}{1 + (a + bi)(c + di)}.\)

To express this in rectangular form, we can multiply the numerator and denominator by the conjugate:

\(\dfrac{a + c + bi + di}{1 + (a + bi)(c + di)} = \dfrac{(a + c + bi + di)((1 - (a + bi)(c + di))}{(1 + (a + bi)(c + di))(1 - (a + bi)(c + di))}.\)

The denominator simplifies to (1 - (a^2 + b^2)(c^2 + d^2)), which is real.  The numerator simplifies to a^2 - b^2 + c^2 - d^2, which is also real.  Therefore, the complex number (z + w)/(zw + 1) is real.

 Jan 9, 2022

16 Online Users

avatar