In triangle ABC, the angle bisector of \(\angle BAC\) meets \(\overline{BC}\) at D such that AD = AB. Line segment \(\overline{AD}\) is extended to E, such that CD = CE and \(\angle DBE = \angle BAD\). Show that triangle ACE is isosceles.
I know this is a writing problem so I'll only give a hint
ALL USERS DO NOT GIVE FULL SOLUTIONS.
Hint: Can you find any similar triangles?