How many ways can you arrange the digits 1, 2, 4, 5, 6, 7, to get a six-digit number that is divisible by 25?
for a number to be divisible by 25, it must end in either 00 (making it a multiple of 100), 25 (a multiple of 100 + 25), 50 (a multiple of 50), or 75 (a multiple of 100 + 75). since 0 isn't in our digits, the digits must be in the form
××××25
or
××××75
where × represents any digit not used. there are 4! ways to arrange the digits that fit the first form and 4! ways for the second, so we have a total of
4!+4!=24+24=48
ways to arrange the digits.