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What is the mass, in grams, of 1.70×1021 molecules of aspirin, C9H8O4?

Guest Mar 29, 2017
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Since the molecular weight of Aspirin - C9H8O4 is equal to:  = 180.157 g/mol =6.022 x 10^23 atoms or molecules, it therefore follows that 1.70 x 10^21 molecules = 1.70 x 10^21 /6.022 x 10^23 x 180.157

=  0.50858 grams.                                       

Guest Mar 29, 2017

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