What is the mass, in grams, of 1.70×1021 molecules of aspirin, C9H8O4?
Since the molecular weight of Aspirin - C9H8O4 is equal to: = 180.157 g/mol =6.022 x 10^23 atoms or molecules, it therefore follows that 1.70 x 10^21 molecules = 1.70 x 10^21 /6.022 x 10^23 x 180.157
= 0.50858 grams.
